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rini:speed_log_notes [2009/04/17 05:07]
ben
rini:speed_log_notes [2009/04/17 06:37]
ben
Line 30: Line 30:
  
 D = Y/X * 1 n.m. D = Y/X * 1 n.m.
 +
 T = Z/3600 T = Z/3600
  
-So:  (Z/X * 1 n.m.) / (Z/3600) = Speed in knots for the sample period Z+So:  (Y/X * 1 n.m.) / (Z/3600) = Speed in knots for the sample period Z
  
-E.G.  If we calibrate 1 n.m. at 2500 clicks (X=2500) and our sample/​update period is 2 seconds (Z=2), and over that period we count 30 clicks (Y=30), then calculated speed would be (30/​2500)/​(2/​3600) = S = 0.012 / 0.0011 1.0909 knots.+E.G.  If we calibrate 1 n.m. at 2500 clicks (X=2500) and our sample/​update period is 2 seconds (Z=2), and over that period we count 10 clicks (Y=10), then calculated speed would be (10/​2500)/​(2/​3600) = S = 0.004 / 0.0006 6.67 knots
 + 
 +Hopefully we get faster turn rates that 5 rotations per second, otherwise it won't be very precise.
 </​blockquote>​ </​blockquote>​
 +
  
  
rini/speed_log_notes.txt · Last modified: 2011/04/11 09:20 by ben